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https://colab.research.google.com/drive/1tohxd91bD2Y3aNItw1mxEXTqMs_AG4oc
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Let us first note that, since ${\ensuremath{\mathcal{L}_\mathrm{ave}}}$ controls the asymptotic shape of the escape to infinity, it is a natural candidate to take part in the description of the asymptotic of the fluid escape, as proposed by [@HN08]. This is demonstrated by Figures \[fig:H-N05-Lave-Asympt\] and \[fig:H-N05-Lave-Asympt\] showing the time evolution of the asymptotic escape area for several simulation runs with different initial data.
The figures suggest that the parameter ${\ensuremath{\mathcal{L}_\mathrm{ave}}}$ plays a role in the description of the asymptotic escape of the fluid due to a pressure term. This also seems to be the case for the boundary deformation function $h^1$, for which Figures \[fig:H-N05-h1\] and \[fig:H-N05-Lave-h1\] indicate a role for ${\ensuremath{\mathcal{L}_\mathrm{ave}}}$ when the boundary deformation function $h^1$ is present.
The standard initial datum for the boundary deformation function is given by the value of the area in the steady state. This can be seen in Figure \[fig:H-Lave-h1-S\], where the evolution of the total area of the fluid domain is depicted together with the evolution of the total area of the domain occupied by the dry skeleton. If the mass of the dry skeleton tends to infinity, the only possibility is that the total area of the fluid domain becomes infinite. This happens when $$\label{eq:Asympt-Laver-limit}
\lim_{t\rightarrow\infty} \int_{\Omega(t)} h^1(t,\cdot) =
\int_{\Omega^S(t)} h^1(t
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