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.Find Original OEM new or used Fiat Seicento Car Spares quickly and e.. flow BMW 5 SERIES 2014 F10 Owner’s Manual, service Fiat DUCATO 244 2005 3.Q:

A function that returns a hash and has a default value?

The following works,
def h1(a=1)
a
end

But is there any better way to do this?
In my case, it won’t be applicable to always change the default value.

A:

Doing it this way:
def h1(a=1)
a
end

is just the default single line version. By using the lambda:
def h1(a=lambda{1})
a
end

you can still have a default value and call it with no arguments, and you don’t have to create the lambda every time. You also don’t have to define a method in this case. But you would have to define methods to access the value of the first argument.
To give an example:
def print_result(h)
print h.first
end

print_result(h1(2)) # 1
print_result(h1(3)) # 2

is the same as:
def print_result(h)
print h.first
end

print_result(h1) # 1
print_result(h1(2)) # 1
print_result(h1(3)) # 2

You can also mix it around:
print_result(h1(3,2)) # 3

is the same as:
def print_result(h)
print h.first
end

print_result(h1(3,2)) # 3

A:

Ruby offers a number of ways to define methods.
There is the method defined in your question;
def h1(a=1)
a
end

Which is really just a shortcut for defining a method. It’s conventional to use single quotes to represent a method and double quotes to represent a string, so we could also write it this way:
def h1(‚a = 1‘)
a
end

Next we have block syntax.
def h1(a = 1)
a
end

This uses
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